BigSis Academy

The upper and lower halves of the first figure in each row “pass through” each other, over lapping in the second figure and ending up on opposite sides in the third figure.

Rotation inside of the shape.

Each row is an addition problem. The total number of sides of all the shapes in the first two figure added together equals the total number of sides of all the shapes in the third figure.

The number of sides decreases as you move from left to right.

In each row, the number of sides of the first two shapes added together equals the number of circles in the colored in square. Since the third row has a square and a trapezoid, each 4 sides, the answer must be a colored square with 8 circles.

In each row, the shape is cut 1/4 and 1/2.

In each row, the reduced size shapes in the first two figures is contained in the third figure.

In each row, the smaller figure in the second figure is taken out and increased in size.

In each low, the third shape from left to tight is also the shape that is rotating 90 degrees around the shapes in the row. Since the small shape moving around the figure in the third row is a triangle, the answer must include a triangle as well.

Count the number of sides. It’s an addition in each row.

In each row, there is a common shape, but in different sizes. In the first row, there is a small triangle in the first figure, a middle triangle in the second figure, and a big triangle in the third figure. In the second role, we look at the circle, which has a similar pattern. For the third row, we look at the squares. So the answer should be with a big square, which is d.

The arrows are pointing in the direction that the colored square will move to next. Since the last colored square was in the bottom right corner and the arrow pointed left, the answer must have a green square in the bottom left corner.